3.171 \(\int x^3 (a+b \tanh ^{-1}(\frac {c}{x^2}))^2 \, dx\)

Optimal. Leaf size=94 \[ -\frac {1}{4} c^2 \left (a+b \coth ^{-1}\left (\frac {x^2}{c}\right )\right )^2+\frac {1}{2} b c x^2 \left (a+b \coth ^{-1}\left (\frac {x^2}{c}\right )\right )+\frac {1}{4} x^4 \left (a+b \coth ^{-1}\left (\frac {x^2}{c}\right )\right )^2+\frac {1}{4} b^2 c^2 \log \left (1-\frac {c^2}{x^4}\right )+b^2 c^2 \log (x) \]

[Out]

1/2*b*c*x^2*(a+b*arccoth(x^2/c))-1/4*c^2*(a+b*arccoth(x^2/c))^2+1/4*x^4*(a+b*arccoth(x^2/c))^2+1/4*b^2*c^2*ln(
1-c^2/x^4)+b^2*c^2*ln(x)

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Rubi [C]  time = 1.30, antiderivative size = 599, normalized size of antiderivative = 6.37, number of steps used = 59, number of rules used = 33, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 2.063, Rules used = {6099, 2454, 2398, 2411, 2347, 2344, 2301, 2316, 2315, 2314, 31, 2455, 263, 266, 43, 193, 6742, 30, 2557, 12, 2466, 2448, 2462, 260, 2416, 2394, 2393, 2391, 2410, 2395, 36, 29, 2390} \[ -\frac {1}{8} b^2 c^2 \text {PolyLog}\left (2,-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {PolyLog}\left (2,\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {PolyLog}\left (2,\frac {c-x^2}{2 c}\right )-\frac {1}{8} b^2 c^2 \text {PolyLog}\left (2,\frac {c+x^2}{2 c}\right )+\frac {1}{8} b^2 c^2 \text {PolyLog}\left (2,\frac {c+x^2}{c}\right )+\frac {1}{8} b^2 c^2 \text {PolyLog}\left (2,1-\frac {x^2}{c}\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{4} a b c x^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{4} a b x^4 \log \left (\frac {c}{x^2}+1\right )+\frac {1}{8} b c x^2 \left (1-\frac {c}{x^2}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} b^2 c^2 \log ^2\left (\frac {c}{x^2}+1\right )+\frac {1}{8} b^2 c^2 \log \left (\frac {c}{x^2}+1\right )+\frac {1}{8} b^2 c^2 \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (\frac {c}{x^2}+1\right ) \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (\frac {x^2}{c}\right ) \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (-\frac {x^2}{c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (\frac {c-x^2}{2 c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (c-x^2\right ) \log \left (\frac {c+x^2}{2 c}\right )+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{16} b^2 x^4 \log ^2\left (\frac {c}{x^2}+1\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (\frac {c}{x^2}+1\right )-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (\frac {c}{x^2}+1\right ) \]

Warning: Unable to verify antiderivative.

[In]

Int[x^3*(a + b*ArcTanh[c/x^2])^2,x]

[Out]

(a*b*c*x^2)/4 - (b^2*c*x^2*Log[1 - c/x^2])/8 + (b*c*(1 - c/x^2)*x^2*(2*a - b*Log[1 - c/x^2]))/8 - (c^2*(2*a -
b*Log[1 - c/x^2])^2)/16 + (x^4*(2*a - b*Log[1 - c/x^2])^2)/16 + (b^2*c^2*Log[1 + c/x^2])/8 + (b^2*c*x^2*Log[1
+ c/x^2])/4 + (a*b*x^4*Log[1 + c/x^2])/4 - (b^2*x^4*Log[1 - c/x^2]*Log[1 + c/x^2])/8 - (b^2*c^2*Log[1 + c/x^2]
^2)/16 + (b^2*x^4*Log[1 + c/x^2]^2)/16 + (a*b*c^2*Log[x])/2 + (b^2*c^2*Log[x])/2 + (b^2*c^2*Log[c - x^2])/8 +
(b^2*c^2*Log[1 + c/x^2]*Log[c - x^2])/8 + (b^2*c^2*Log[x^2/c]*Log[c - x^2])/8 - (a*b*c^2*Log[c + x^2])/4 + (b^
2*c^2*Log[c + x^2])/8 + (b^2*c^2*Log[1 - c/x^2]*Log[c + x^2])/8 + (b^2*c^2*Log[-(x^2/c)]*Log[c + x^2])/8 - (b^
2*c^2*Log[(c - x^2)/(2*c)]*Log[c + x^2])/8 - (b^2*c^2*Log[c - x^2]*Log[(c + x^2)/(2*c)])/8 - (b^2*c^2*PolyLog[
2, -(c/x^2)])/8 - (b^2*c^2*PolyLog[2, c/x^2])/8 - (b^2*c^2*PolyLog[2, (c - x^2)/(2*c)])/8 - (b^2*c^2*PolyLog[2
, (c + x^2)/(2*c)])/8 + (b^2*c^2*PolyLog[2, (c + x^2)/c])/8 + (b^2*c^2*PolyLog[2, 1 - x^2/c])/8

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 36

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Dist[b/(b*c - a*d), Int[1/(a + b*x), x], x] -
Dist[d/(b*c - a*d), Int[1/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 193

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(n*p)*(b + a/x^n)^p, x] /; FreeQ[{a, b}, x] && LtQ[n, 0]
&& IntegerQ[p]

Rule 260

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 263

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(m + n*p)*(b + a/x^n)^p, x] /; FreeQ[{a, b, m
, n}, x] && IntegerQ[p] && NegQ[n]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2314

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_) + (e_.)*(x_)^(r_.))^(q_), x_Symbol] :> Simp[(x*(d + e*x^r)^(q
+ 1)*(a + b*Log[c*x^n]))/d, x] - Dist[(b*n)/d, Int[(d + e*x^r)^(q + 1), x], x] /; FreeQ[{a, b, c, d, e, n, q,
r}, x] && EqQ[r*(q + 1) + 1, 0]

Rule 2315

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[PolyLog[2, 1 - c*x]/e, x] /; FreeQ[{c, d, e}, x] &
& EqQ[e + c*d, 0]

Rule 2316

Int[((a_.) + Log[(c_.)*(x_)]*(b_.))/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[((a + b*Log[-((c*d)/e)])*Log[d + e*
x])/e, x] + Dist[b, Int[Log[-((e*x)/d)]/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e}, x] && GtQ[-((c*d)/e), 0]

Rule 2344

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x_Symbol] :> Dist[1/d, Int[(a + b*
Log[c*x^n])^p/x, x], x] - Dist[e/d, Int[(a + b*Log[c*x^n])^p/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, n}, x]
&& IGtQ[p, 0]

Rule 2347

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_))/(x_), x_Symbol] :> Dist[1/d, Int[((
d + e*x)^(q + 1)*(a + b*Log[c*x^n])^p)/x, x], x] - Dist[e/d, Int[(d + e*x)^q*(a + b*Log[c*x^n])^p, x], x] /; F
reeQ[{a, b, c, d, e, n}, x] && IGtQ[p, 0] && LtQ[q, -1] && IntegerQ[2*q]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2395

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[((f + g
*x)^(q + 1)*(a + b*Log[c*(d + e*x)^n]))/(g*(q + 1)), x] - Dist[(b*e*n)/(g*(q + 1)), Int[(f + g*x)^(q + 1)/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*f - d*g, 0] && NeQ[q, -1]

Rule 2398

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[((
f + g*x)^(q + 1)*(a + b*Log[c*(d + e*x)^n])^p)/(g*(q + 1)), x] - Dist[(b*e*n*p)/(g*(q + 1)), Int[((f + g*x)^(q
+ 1)*(a + b*Log[c*(d + e*x)^n])^(p - 1))/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*
f - d*g, 0] && GtQ[p, 0] && NeQ[q, -1] && IntegersQ[2*p, 2*q] && ( !IGtQ[q, 0] || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2410

Int[(Log[(c_.)*((d_) + (e_.)*(x_))]*(x_)^(m_.))/((f_) + (g_.)*(x_)), x_Symbol] :> Int[ExpandIntegrand[Log[c*(d
+ e*x)], x^m/(f + g*x), x], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[e*f - d*g, 0] && EqQ[c*d, 1] && IntegerQ[m
]

Rule 2411

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + (g_.)*(x_))^(q_.)*((h_.) + (i_.)*(x_))
^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[((g*x)/e)^q*((e*h - d*i)/e + (i*x)/e)^r*(a + b*Log[c*x^n])^p, x], x,
d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, n, p, q, r}, x] && EqQ[e*f - d*g, 0] && (IGtQ[p, 0] || IGtQ[
r, 0]) && IntegerQ[2*r]

Rule 2416

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((h_.)*(x_))^(m_.)*((f_) + (g_.)*(x_)^(r_.))^(q
_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*Log[c*(d + e*x)^n])^p, (h*x)^m*(f + g*x^r)^q, x], x] /; FreeQ[{a,
b, c, d, e, f, g, h, m, n, p, q, r}, x] && IntegerQ[m] && IntegerQ[q]

Rule 2448

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)], x_Symbol] :> Simp[x*Log[c*(d + e*x^n)^p], x] - Dist[e*n*p, Int[
x^n/(d + e*x^n), x], x] /; FreeQ[{c, d, e, n, p}, x]

Rule 2454

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rule 2455

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.)*(x_))^(m_.), x_Symbol] :> Simp[((f*x)^(m
+ 1)*(a + b*Log[c*(d + e*x^n)^p]))/(f*(m + 1)), x] - Dist[(b*e*n*p)/(f*(m + 1)), Int[(x^(n - 1)*(f*x)^(m + 1))
/(d + e*x^n), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && NeQ[m, -1]

Rule 2462

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[f +
g*x]*(a + b*Log[c*(d + e*x^n)^p]))/g, x] - Dist[(b*e*n*p)/g, Int[(x^(n - 1)*Log[f + g*x])/(d + e*x^n), x], x]
/; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && RationalQ[n]

Rule 2466

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.)*((f_.) + (g_.)*(x_))^(r_.), x_S
ymbol] :> Int[ExpandIntegrand[(a + b*Log[c*(d + e*x^n)^p])^q, x^m*(f + g*x)^r, x], x] /; FreeQ[{a, b, c, d, e,
f, g, n, p, q}, x] && IntegerQ[m] && IntegerQ[r]

Rule 2557

Int[Log[v_]*Log[w_]*(u_), x_Symbol] :> With[{z = IntHide[u, x]}, Dist[Log[v]*Log[w], z, x] + (-Int[SimplifyInt
egrand[(z*Log[w]*D[v, x])/v, x], x] - Int[SimplifyIntegrand[(z*Log[v]*D[w, x])/w, x], x]) /; InverseFunctionFr
eeQ[z, x]] /; InverseFunctionFreeQ[v, x] && InverseFunctionFreeQ[w, x]

Rule 6099

Int[((a_.) + ArcTanh[(c_.)*(x_)^(n_)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(d*x)^
m*(a + (b*Log[1 + c*x^n])/2 - (b*Log[1 - c*x^n])/2)^p, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && IGtQ[p, 0] &&
IntegerQ[m] && IntegerQ[n]

Rule 6742

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rubi steps

\begin {align*} \int x^3 \left (a+b \tanh ^{-1}\left (\frac {c}{x^2}\right )\right )^2 \, dx &=\int \left (\frac {1}{4} x^3 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2-\frac {1}{2} b x^3 \left (-2 a+b \log \left (1-\frac {c}{x^2}\right )\right ) \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 x^3 \log ^2\left (1+\frac {c}{x^2}\right )\right ) \, dx\\ &=\frac {1}{4} \int x^3 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2 \, dx-\frac {1}{2} b \int x^3 \left (-2 a+b \log \left (1-\frac {c}{x^2}\right )\right ) \log \left (1+\frac {c}{x^2}\right ) \, dx+\frac {1}{4} b^2 \int x^3 \log ^2\left (1+\frac {c}{x^2}\right ) \, dx\\ &=-\left (\frac {1}{8} \operatorname {Subst}\left (\int \frac {(2 a-b \log (1-c x))^2}{x^3} \, dx,x,\frac {1}{x^2}\right )\right )-\frac {1}{4} b \operatorname {Subst}\left (\int x \left (-2 a+b \log \left (1-\frac {c}{x}\right )\right ) \log \left (1+\frac {c}{x}\right ) \, dx,x,x^2\right )-\frac {1}{8} b^2 \operatorname {Subst}\left (\int \frac {\log ^2(1+c x)}{x^3} \, dx,x,\frac {1}{x^2}\right )\\ &=\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )-\frac {1}{4} b \operatorname {Subst}\left (\int \left (-2 a x \log \left (1+\frac {c}{x}\right )+b x \log \left (1-\frac {c}{x}\right ) \log \left (1+\frac {c}{x}\right )\right ) \, dx,x,x^2\right )-\frac {1}{8} (b c) \operatorname {Subst}\left (\int \frac {2 a-b \log (1-c x)}{x^2 (1-c x)} \, dx,x,\frac {1}{x^2}\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {\log (1+c x)}{x^2 (1+c x)} \, dx,x,\frac {1}{x^2}\right )\\ &=\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{8} b \operatorname {Subst}\left (\int \frac {2 a-b \log (x)}{x \left (\frac {1}{c}-\frac {x}{c}\right )^2} \, dx,x,1-\frac {c}{x^2}\right )+\frac {1}{2} (a b) \operatorname {Subst}\left (\int x \log \left (1+\frac {c}{x}\right ) \, dx,x,x^2\right )-\frac {1}{4} b^2 \operatorname {Subst}\left (\int x \log \left (1-\frac {c}{x}\right ) \log \left (1+\frac {c}{x}\right ) \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (\frac {\log (1+c x)}{x^2}-\frac {c \log (1+c x)}{x}+\frac {c^2 \log (1+c x)}{1+c x}\right ) \, dx,x,\frac {1}{x^2}\right )\\ &=\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{8} b \operatorname {Subst}\left (\int \frac {2 a-b \log (x)}{\left (\frac {1}{c}-\frac {x}{c}\right )^2} \, dx,x,1-\frac {c}{x^2}\right )+\frac {1}{4} b^2 \operatorname {Subst}\left (\int \frac {c x \log \left (1-\frac {c}{x}\right )}{2 (-c-x)} \, dx,x,x^2\right )+\frac {1}{4} b^2 \operatorname {Subst}\left (\int \frac {c x \log \left (1+\frac {c}{x}\right )}{-2 c+2 x} \, dx,x,x^2\right )+\frac {1}{8} (b c) \operatorname {Subst}\left (\int \frac {2 a-b \log (x)}{x \left (\frac {1}{c}-\frac {x}{c}\right )} \, dx,x,1-\frac {c}{x^2}\right )+\frac {1}{4} (a b c) \operatorname {Subst}\left (\int \frac {1}{1+\frac {c}{x}} \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {\log (1+c x)}{x^2} \, dx,x,\frac {1}{x^2}\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (1+c x)}{x} \, dx,x,\frac {1}{x^2}\right )-\frac {1}{8} \left (b^2 c^3\right ) \operatorname {Subst}\left (\int \frac {\log (1+c x)}{1+c x} \, dx,x,\frac {1}{x^2}\right )\\ &=\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )+\frac {1}{8} (b c) \operatorname {Subst}\left (\int \frac {2 a-b \log (x)}{\frac {1}{c}-\frac {x}{c}} \, dx,x,1-\frac {c}{x^2}\right )+\frac {1}{4} (a b c) \operatorname {Subst}\left (\int \frac {x}{c+x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {1}{c}-\frac {x}{c}} \, dx,x,1-\frac {c}{x^2}\right )+\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x \log \left (1-\frac {c}{x}\right )}{-c-x} \, dx,x,x^2\right )+\frac {1}{4} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x \log \left (1+\frac {c}{x}\right )}{-2 c+2 x} \, dx,x,x^2\right )+\frac {1}{8} \left (b c^2\right ) \operatorname {Subst}\left (\int \frac {2 a-b \log (x)}{x} \, dx,x,1-\frac {c}{x^2}\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{x (1+c x)} \, dx,x,\frac {1}{x^2}\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1+\frac {c}{x^2}\right )\\ &=\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{4} b^2 c^2 \log (x)-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )+\frac {1}{4} (a b c) \operatorname {Subst}\left (\int \left (1-\frac {c}{c+x}\right ) \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (-\log \left (1-\frac {c}{x}\right )+\frac {c \log \left (1-\frac {c}{x}\right )}{c+x}\right ) \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {\log (x)}{\frac {1}{c}-\frac {x}{c}} \, dx,x,1-\frac {c}{x^2}\right )+\frac {1}{4} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (\frac {1}{2} \log \left (1+\frac {c}{x}\right )-\frac {c \log \left (1+\frac {c}{x}\right )}{2 (c-x)}\right ) \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{x} \, dx,x,\frac {1}{x^2}\right )+\frac {1}{8} \left (b^2 c^3\right ) \operatorname {Subst}\left (\int \frac {1}{1+c x} \, dx,x,\frac {1}{x^2}\right )\\ &=\frac {1}{4} a b c x^2+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{8} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)-\frac {1}{4} a b c^2 \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \log \left (1-\frac {c}{x}\right ) \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \log \left (1+\frac {c}{x}\right ) \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {c}{x}\right )}{c+x} \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {c}{x}\right )}{c-x} \, dx,x,x^2\right )\\ &=\frac {1}{4} a b c x^2-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right ) \log \left (c-x^2\right )-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1-\frac {c}{x}\right ) x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1+\frac {c}{x}\right ) x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^3\right ) \operatorname {Subst}\left (\int \frac {\log (c-x)}{\left (1+\frac {c}{x}\right ) x^2} \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c^3\right ) \operatorname {Subst}\left (\int \frac {\log (c+x)}{\left (1-\frac {c}{x}\right ) x^2} \, dx,x,x^2\right )\\ &=\frac {1}{4} a b c x^2-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right ) \log \left (c-x^2\right )-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{-c+x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{c+x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^3\right ) \operatorname {Subst}\left (\int \left (\frac {\log (c-x)}{c x}-\frac {\log (c-x)}{c (c+x)}\right ) \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c^3\right ) \operatorname {Subst}\left (\int \left (-\frac {\log (c+x)}{c (c-x)}-\frac {\log (c+x)}{c x}\right ) \, dx,x,x^2\right )\\ &=\frac {1}{4} a b c x^2-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{8} b^2 c^2 \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right ) \log \left (c-x^2\right )-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (c-x)}{x} \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (c-x)}{c+x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (c+x)}{c-x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (c+x)}{x} \, dx,x,x^2\right )\\ &=\frac {1}{4} a b c x^2-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{8} b^2 c^2 \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right ) \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (\frac {x^2}{c}\right ) \log \left (c-x^2\right )-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (-\frac {x^2}{c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (\frac {c-x^2}{2 c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (c-x^2\right ) \log \left (\frac {c+x^2}{2 c}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {-c-x}{2 c}\right )}{c-x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (\frac {c-x}{2 c}\right )}{c+x} \, dx,x,x^2\right )-\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {x}{c}\right )}{c+x} \, dx,x,x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (\frac {x}{c}\right )}{c-x} \, dx,x,x^2\right )\\ &=\frac {1}{4} a b c x^2-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{8} b^2 c^2 \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right ) \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (\frac {x^2}{c}\right ) \log \left (c-x^2\right )-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (-\frac {x^2}{c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (\frac {c-x^2}{2 c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (c-x^2\right ) \log \left (\frac {c+x^2}{2 c}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )+\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c+x^2}{c}\right )+\frac {1}{8} b^2 c^2 \text {Li}_2\left (1-\frac {x^2}{c}\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2 c}\right )}{x} \, dx,x,c-x^2\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2 c}\right )}{x} \, dx,x,c+x^2\right )\\ &=\frac {1}{4} a b c x^2-\frac {1}{8} b^2 c x^2 \log \left (1-\frac {c}{x^2}\right )+\frac {1}{8} b c \left (1-\frac {c}{x^2}\right ) x^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )-\frac {1}{16} c^2 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{16} x^4 \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} b^2 c x^2 \log \left (1+\frac {c}{x^2}\right )+\frac {1}{4} a b x^4 \log \left (1+\frac {c}{x^2}\right )-\frac {1}{8} b^2 x^4 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )-\frac {1}{16} b^2 c^2 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{16} b^2 x^4 \log ^2\left (1+\frac {c}{x^2}\right )+\frac {1}{2} a b c^2 \log (x)+\frac {1}{2} b^2 c^2 \log (x)+\frac {1}{8} b^2 c^2 \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1+\frac {c}{x^2}\right ) \log \left (c-x^2\right )+\frac {1}{8} b^2 c^2 \log \left (\frac {x^2}{c}\right ) \log \left (c-x^2\right )-\frac {1}{4} a b c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (c+x^2\right )+\frac {1}{8} b^2 c^2 \log \left (-\frac {x^2}{c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (\frac {c-x^2}{2 c}\right ) \log \left (c+x^2\right )-\frac {1}{8} b^2 c^2 \log \left (c-x^2\right ) \log \left (\frac {c+x^2}{2 c}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (-\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c}{x^2}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c-x^2}{2 c}\right )-\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c+x^2}{2 c}\right )+\frac {1}{8} b^2 c^2 \text {Li}_2\left (\frac {c+x^2}{c}\right )+\frac {1}{8} b^2 c^2 \text {Li}_2\left (1-\frac {x^2}{c}\right )\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 104, normalized size = 1.11 \[ \frac {1}{4} \left (a^2 x^4+b c^2 (a+b) \log \left (x^2-c\right )-a b c^2 \log \left (c+x^2\right )+2 a b c x^2+2 b x^2 \tanh ^{-1}\left (\frac {c}{x^2}\right ) \left (a x^2+b c\right )+b^2 c^2 \log \left (c+x^2\right )+b^2 \left (x^4-c^2\right ) \tanh ^{-1}\left (\frac {c}{x^2}\right )^2\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x^3*(a + b*ArcTanh[c/x^2])^2,x]

[Out]

(2*a*b*c*x^2 + a^2*x^4 + 2*b*x^2*(b*c + a*x^2)*ArcTanh[c/x^2] + b^2*(-c^2 + x^4)*ArcTanh[c/x^2]^2 + b*(a + b)*
c^2*Log[-c + x^2] - a*b*c^2*Log[c + x^2] + b^2*c^2*Log[c + x^2])/4

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fricas [A]  time = 0.42, size = 126, normalized size = 1.34 \[ \frac {1}{4} \, a^{2} x^{4} + \frac {1}{2} \, a b c x^{2} - \frac {1}{4} \, {\left (a b - b^{2}\right )} c^{2} \log \left (x^{2} + c\right ) + \frac {1}{4} \, {\left (a b + b^{2}\right )} c^{2} \log \left (x^{2} - c\right ) + \frac {1}{16} \, {\left (b^{2} x^{4} - b^{2} c^{2}\right )} \log \left (\frac {x^{2} + c}{x^{2} - c}\right )^{2} + \frac {1}{4} \, {\left (a b x^{4} + b^{2} c x^{2}\right )} \log \left (\frac {x^{2} + c}{x^{2} - c}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*arctanh(c/x^2))^2,x, algorithm="fricas")

[Out]

1/4*a^2*x^4 + 1/2*a*b*c*x^2 - 1/4*(a*b - b^2)*c^2*log(x^2 + c) + 1/4*(a*b + b^2)*c^2*log(x^2 - c) + 1/16*(b^2*
x^4 - b^2*c^2)*log((x^2 + c)/(x^2 - c))^2 + 1/4*(a*b*x^4 + b^2*c*x^2)*log((x^2 + c)/(x^2 - c))

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giac [B]  time = 0.29, size = 327, normalized size = 3.48 \[ -\frac {2 \, b^{2} c^{3} \log \left (\frac {x^{2} + c}{x^{2} - c} - 1\right ) - 2 \, b^{2} c^{3} \log \left (\frac {x^{2} + c}{x^{2} - c}\right ) - \frac {{\left (x^{2} + c\right )} b^{2} c^{3} \log \left (\frac {x^{2} + c}{x^{2} - c}\right )^{2}}{{\left (x^{2} - c\right )} {\left (\frac {{\left (x^{2} + c\right )}^{2}}{{\left (x^{2} - c\right )}^{2}} - \frac {2 \, {\left (x^{2} + c\right )}}{x^{2} - c} + 1\right )}} - \frac {2 \, {\left (\frac {2 \, {\left (x^{2} + c\right )} a b c^{3}}{x^{2} - c} + \frac {{\left (x^{2} + c\right )} b^{2} c^{3}}{x^{2} - c} - b^{2} c^{3}\right )} \log \left (\frac {x^{2} + c}{x^{2} - c}\right )}{\frac {{\left (x^{2} + c\right )}^{2}}{{\left (x^{2} - c\right )}^{2}} - \frac {2 \, {\left (x^{2} + c\right )}}{x^{2} - c} + 1} - \frac {4 \, {\left (\frac {{\left (x^{2} + c\right )} a^{2} c^{3}}{x^{2} - c} + \frac {{\left (x^{2} + c\right )} a b c^{3}}{x^{2} - c} - a b c^{3}\right )}}{\frac {{\left (x^{2} + c\right )}^{2}}{{\left (x^{2} - c\right )}^{2}} - \frac {2 \, {\left (x^{2} + c\right )}}{x^{2} - c} + 1}}{4 \, c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*arctanh(c/x^2))^2,x, algorithm="giac")

[Out]

-1/4*(2*b^2*c^3*log((x^2 + c)/(x^2 - c) - 1) - 2*b^2*c^3*log((x^2 + c)/(x^2 - c)) - (x^2 + c)*b^2*c^3*log((x^2
+ c)/(x^2 - c))^2/((x^2 - c)*((x^2 + c)^2/(x^2 - c)^2 - 2*(x^2 + c)/(x^2 - c) + 1)) - 2*(2*(x^2 + c)*a*b*c^3/
(x^2 - c) + (x^2 + c)*b^2*c^3/(x^2 - c) - b^2*c^3)*log((x^2 + c)/(x^2 - c))/((x^2 + c)^2/(x^2 - c)^2 - 2*(x^2
+ c)/(x^2 - c) + 1) - 4*((x^2 + c)*a^2*c^3/(x^2 - c) + (x^2 + c)*a*b*c^3/(x^2 - c) - a*b*c^3)/((x^2 + c)^2/(x^
2 - c)^2 - 2*(x^2 + c)/(x^2 - c) + 1))/c

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maple [F(-2)]  time = 180.00, size = 0, normalized size = 0.00 \[ \int x^{3} \left (a +b \arctanh \left (\frac {c}{x^{2}}\right )\right )^{2}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a+b*arctanh(c/x^2))^2,x)

[Out]

int(x^3*(a+b*arctanh(c/x^2))^2,x)

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maxima [A]  time = 0.33, size = 157, normalized size = 1.67 \[ \frac {1}{4} \, b^{2} x^{4} \operatorname {artanh}\left (\frac {c}{x^{2}}\right )^{2} + \frac {1}{4} \, a^{2} x^{4} + \frac {1}{4} \, {\left (2 \, x^{4} \operatorname {artanh}\left (\frac {c}{x^{2}}\right ) + {\left (2 \, x^{2} - c \log \left (x^{2} + c\right ) + c \log \left (x^{2} - c\right )\right )} c\right )} a b + \frac {1}{16} \, {\left ({\left (\log \left (x^{2} + c\right )^{2} - 2 \, {\left (\log \left (x^{2} + c\right ) - 2\right )} \log \left (x^{2} - c\right ) + \log \left (x^{2} - c\right )^{2} + 4 \, \log \left (x^{2} + c\right )\right )} c^{2} + 4 \, {\left (2 \, x^{2} - c \log \left (x^{2} + c\right ) + c \log \left (x^{2} - c\right )\right )} c \operatorname {artanh}\left (\frac {c}{x^{2}}\right )\right )} b^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*arctanh(c/x^2))^2,x, algorithm="maxima")

[Out]

1/4*b^2*x^4*arctanh(c/x^2)^2 + 1/4*a^2*x^4 + 1/4*(2*x^4*arctanh(c/x^2) + (2*x^2 - c*log(x^2 + c) + c*log(x^2 -
c))*c)*a*b + 1/16*((log(x^2 + c)^2 - 2*(log(x^2 + c) - 2)*log(x^2 - c) + log(x^2 - c)^2 + 4*log(x^2 + c))*c^2
+ 4*(2*x^2 - c*log(x^2 + c) + c*log(x^2 - c))*c*arctanh(c/x^2))*b^2

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mupad [B]  time = 1.21, size = 247, normalized size = 2.63 \[ \frac {a^2\,x^4}{4}-\frac {a\,b\,c^2\,\ln \left (x^2+c\right )}{4}+\frac {a\,b\,c^2\,\ln \left (x^2-c\right )}{4}+\frac {a\,b\,c\,x^2}{2}+\frac {a\,b\,x^4\,\ln \left (x^2+c\right )}{4}-\frac {a\,b\,x^4\,\ln \left (x^2-c\right )}{4}-\frac {b^2\,c^2\,{\ln \left (x^2+c\right )}^2}{16}+\frac {b^2\,c^2\,\ln \left (x^2+c\right )\,\ln \left (x^2-c\right )}{8}+\frac {b^2\,c^2\,\ln \left (x^2+c\right )}{4}-\frac {b^2\,c^2\,{\ln \left (x^2-c\right )}^2}{16}+\frac {b^2\,c^2\,\ln \left (x^2-c\right )}{4}+\frac {b^2\,c\,x^2\,\ln \left (x^2+c\right )}{4}-\frac {b^2\,c\,x^2\,\ln \left (x^2-c\right )}{4}+\frac {b^2\,x^4\,{\ln \left (x^2+c\right )}^2}{16}-\frac {b^2\,x^4\,\ln \left (x^2+c\right )\,\ln \left (x^2-c\right )}{8}+\frac {b^2\,x^4\,{\ln \left (x^2-c\right )}^2}{16} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a + b*atanh(c/x^2))^2,x)

[Out]

(a^2*x^4)/4 + (b^2*c^2*log(x^2 - c))/4 - (b^2*c^2*log(c + x^2)^2)/16 + (b^2*x^4*log(c + x^2)^2)/16 - (b^2*c^2*
log(x^2 - c)^2)/16 + (b^2*x^4*log(x^2 - c)^2)/16 + (b^2*c^2*log(c + x^2))/4 + (a*b*x^4*log(c + x^2))/4 + (a*b*
c^2*log(x^2 - c))/4 + (b^2*c^2*log(c + x^2)*log(x^2 - c))/8 + (a*b*c*x^2)/2 - (a*b*x^4*log(x^2 - c))/4 + (b^2*
c*x^2*log(c + x^2))/4 - (b^2*x^4*log(c + x^2)*log(x^2 - c))/8 - (b^2*c*x^2*log(x^2 - c))/4 - (a*b*c^2*log(c +
x^2))/4

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sympy [C]  time = 6.12, size = 151, normalized size = 1.61 \[ \frac {a^{2} x^{4}}{4} - \frac {a b c^{2} \operatorname {atanh}{\left (\frac {c}{x^{2}} \right )}}{2} + \frac {a b c x^{2}}{2} + \frac {a b x^{4} \operatorname {atanh}{\left (\frac {c}{x^{2}} \right )}}{2} + \frac {b^{2} c^{2} \log {\left (- i \sqrt {c} + x \right )}}{2} + \frac {b^{2} c^{2} \log {\left (i \sqrt {c} + x \right )}}{2} - \frac {b^{2} c^{2} \operatorname {atanh}^{2}{\left (\frac {c}{x^{2}} \right )}}{4} - \frac {b^{2} c^{2} \operatorname {atanh}{\left (\frac {c}{x^{2}} \right )}}{2} + \frac {b^{2} c x^{2} \operatorname {atanh}{\left (\frac {c}{x^{2}} \right )}}{2} + \frac {b^{2} x^{4} \operatorname {atanh}^{2}{\left (\frac {c}{x^{2}} \right )}}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(a+b*atanh(c/x**2))**2,x)

[Out]

a**2*x**4/4 - a*b*c**2*atanh(c/x**2)/2 + a*b*c*x**2/2 + a*b*x**4*atanh(c/x**2)/2 + b**2*c**2*log(-I*sqrt(c) +
x)/2 + b**2*c**2*log(I*sqrt(c) + x)/2 - b**2*c**2*atanh(c/x**2)**2/4 - b**2*c**2*atanh(c/x**2)/2 + b**2*c*x**2
*atanh(c/x**2)/2 + b**2*x**4*atanh(c/x**2)**2/4

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